10a^2+80a-200=0

Solution for 10a^2+80a-200=0 equation:

10a^2+80a-200=0

a = 10; b = 80; c = -200;
Δ = b2-4ac
Δ = 802-4·10·(-200)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-120}{2*10}=\frac{-200}{20}
=-10
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+120}{2*10}=\frac{40}{20}
=2
$